CAT 2020 Exam Shift 3 Solved Paper

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Question : 67 of 76

Marks: +1, -0

Let

{N}, {x}

and

{y}

be positive integers such that

N=x+y, 2 < x < 10

and

14 < y < 23

. If

N > 25

, then how many distinct values are possible for

{N} ?

Your Answer:

Solution:

Given,

2 < x < 10

and

14 < y < 23 ⇒ 17 < (x+y) < 32

i.e.

17 < N < 32

But

N > 25

hence

25 < N < 32

N can take 6 distinct values.

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