CAT 2019 Shift 2 Paper

Question : 99 of 100

Marks: +1, -0

A shopkeeper sells two tables, each procured at cost price p, to Amal and Asim at a profit of 20% and at a loss of 20%, respectively. Amal sells his table to Bimal at a profit of 30%, while Asim sells his table to Barun at a loss of 30%. If the amounts paid by Bimal and Barun are x and y, respectively, then

(x -y) / p

equals

0.50
1
1.2
0.7

Validate

Solution:

Cost of table for Aman

=1.2 {p}

Cost of table for Asim

=0.8 {p}

Aman sells to Bimal at

1.3 × 1.2 {p}=1.56 {p}

=cost of table for Bimal =

{x}

Asim sells table to Barun at

0.7 × 0.8 {p}=0.56 {p}=

cost of table for Barun

= {y}

Therefore,

\;{x-y}/{p}=\;{1.56 p-0.56 p}/{p}=1

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