CAT 2019 Shift 2 Paper

Let their scores after review be $11\mathit{x},10\mathit{x},$ and $3\mathit{x}$ respectively.
Therefore, their scores before review was: $\left(11\mathit{x}-6\right),10\mathit{x}-6)$ and $\left(3\mathit{x}-6\right)$ respectively.
Given, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali.
$\Rightarrow 12\left(3\mathit{x}-6\right)=21\mathit{x}-12$
$\Rightarrow 36\mathit{x}-72=21\mathit{x}-12$
$\Rightarrow 36\mathit{x}-21\mathit{x}=72-12=60$
$\Rightarrow \mathit{x}=4$
Now, Anjali's score - Rama's score $=\left(11\mathit{x}-6\right)-\left(3\mathit{x}-6\right)=8\mathit{x}=32$.