CAT 2018 Question Paper Shift 2 Solved Paper

Question : 89 of 100

Marks: +1, -0

For two sets A and B, let AΔB denote the set of elements which belong to A or B but not both. If P = {1,2,3,4}, Q = {2,3,5,6,}, R = {1,3,7,8,9}, S = {2,4,9,10}, then the number of elements in (PΔQ)Δ(RΔS) is
Options

Validate

Solution:

{P}=\{1,2,3,4\}

and

{Q}=\{2,3,5,6,\}

{P} ∆ {Q}=\{1,4,5,6\}

{R}=\{1,3,7,8,9\}

and

{S}=\{2,4,9,10\}

{R} ∆ {S}=\{1,2,3,4,7,8,10\}

( {P} ∆ {Q}) ∆( {R} ∆ {S})=\{2,3,5,6,7,8,10\}

Thus, there are 7 elements in

( {P} ∆ {Q}) ∆( {R} ∆ {S})

.
hence, 7 is the correct answer.

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