CAT 2018 Question Paper Shift 2 Solved Paper

Question : 78 of 100

Marks: +1, -0

A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now
Options

2
4
20.5
35.2
30.3

Validate

Solution:

Final quantity of alcohol in the mixture

=\;{700}/{700+175} ×(\;{90}/{100})^{2} ×[700+175]=567 {ml}

Therefore, final quantity of water in the mixture

=875-567=308 {ml}

Hence, the percentage of water in the mixture

=\;{308}/{875} × 100=35.2 \%

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