CAT 2018 Question Paper Shift 1 Solved Paper

Let the $6\mathit{c}\mathit{m}$ long chord be $\mathit{x}\mathit{c}\mathit{m}$ away from the centre of the circle. Let the radius of the circle be $\mathit{r}\mathit{c}\mathit{m}$
The perpendiculars from the centre of the circle to the chords bisect the chords.
${\mathit{r}}^2={\mathit{x}}^2+3^2={\left(\mathit{x}+1\right)}^2+2^2$
Solving, $\mathit{x}=2$ and $\mathit{r}=\sqrt{13}$