If y={10^x+logx}/\sqrtx; then find \frac{ dy}{dx}

Correct Answer is : 10x(2×log10−1)+2−logx2xx

\frac{ 10^x(2\timeslog10-1)+2-logx}{2x\sqrtx}

\frac{ 10^x(2\timeslog10+1)+2-logx}{2x\sqrtx}

\frac{ 10^x(2-1)+2-logx}{2x\sqrtx}

CA CPT Model Test Paper 2 with solutions for online practice

Question : 180 of 200

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y={10^x+logx}/√x

; then find

{ dy}/{dx}

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