P(A_{1}) = 3/8;P(A_{2}) = 2/3;P(A_{1} \cap A_{2}) = ¼then A_{1} and A_{2} will be:

Correct Answer is : Independent but not exclusive

Mutually exclusive & independent

CA CPT June 2015 Question Paper Quantitative Aptitude for online practice

Question : 38 of 50

Marks: +1, -0

P(A_{1}) = 3/8;

P(A_{2}) = 2/3;

P(A_{1} ∩ A_{2}) = ¼

then

A_{1}

and

A_{2}

will be:

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