{Lt}_{n\to\infty} {(n-1)^{n}}/{n^{n}}=

CA CPT Jun 2017 Question Paper Quantitative Aptitude for online practice

Question : 22 of 50

Marks: +1, -0

{Lt}↙{n→∞}\;\;{(n-1)^{n}}/{n^{n}}=

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