f(x)=\log_{e}( \frac{x-1}{x+1}) \and f^{'}(x)=1 then the value of x =

CA CPT Dec 2016 Question Paper Quantitative Aptitude for online practice

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f(x)=\log_{e}(\;\;{x-1}/{x+1})

\and f^{'}(x)=1

then the value of x =

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