If y=1+ \frac{x}{1!}+ \frac{x^{2}}{2!}+ \frac{x^{3}}{3!}+. . ... . .. . . + \frac{x^{n}}{n!}+..........\infty then \frac{dy}{dx}-y=

CA CPT 2014 Dec Question Paper Quantitative Aptitude for online practice

Question : 24 of 50

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y=1+\;\;{x}/{1!}+\;\;{x^{2}}/{2!}+\;\;{x^{3}}/{3!}+. . ... . .. . .

+\;\;{x^{n}}/{n!}+..........∞

then

{dy}/{dx}-y=

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