The correct relation between hydrolysis constant (K_{h}) and degree of hydrolysis (\alpha) for the following equilibrium is {A}^{-}+ {H}_{2} {O} ⇌ {AH}+ {OH}^{-}

Correct Answer is : α=√KwKa⋅C

\alpha=\sqrt{ {K_{w} \cdot C}/{K_{w}}}

\alpha=\sqrt{ {K_{w}/{K_{a} \cdot C}}

\alpha=\sqrt{ {K_{a} \cdot C}/{K_{w}}}

\alpha=\sqrt{ {K_{a}/{K_{w} \cdot C}}

BSc Nursing GNM 2020 Solved Paper

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The correct relation between hydrolysis constant (Kh) and degree of hydrolysis (α) for the following equilibrium is A−+H2O⇌AH+OH−

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