BSc Nursing GNM 2020 Solved Paper

We knows, dimensions of moment of inertia I=[ML2] Dimensions of moment of force,
F=[MLT−2]
Dimensions of moment of velocity,
v=[LT−2]
Dimensions of moment of work,
W=[ML2T−2]
Dimensions of moment of lengthl=[L]
∴ Dimensions of X
=‌

‌ Dimensions of ‌[IFv2]

‌ Dimensions of ‌[WL3]

=‌

[ML2][MLT−2][LT−2]2

[ML2T−2][L3]

=‌

[M2L5T−4]

[ML5T−2]

=[MT−2]