BSc Nursing GNM 2019 Solved Paper

∆G=∆H−T∆S
Here, ∆G= Gibb's free energy
∆H= Enthalpy change
∆S= Entropy change
T= Temperature
As equilibrium, ∆G=0. Thus, T∆S=∆H, as ∆H and ∆S are + ve, for a reaction to be feasible (spontaneous), ∆G should be -ve.
This can be possible only when
i.e. ‌‌T∆S>Te∆S
‌‌T>Te
[Te= temperature at equilibrium ]