BPSC 69th Prelims Exam 30 Sep 2023 Solved Paper

If two objects of different masses (From the same height) in tree fall near the surface of the Moon will have same speed at any instant because
$\mathrm{h}=\frac{1}{2}\mathrm{gmt}2\left(\mathrm{u}=0\right)$
$\mathrm{t}2=2\mathrm{h}∕\mathrm{gm}$
$\mathrm{v}=\mathrm{gmt}=\mathrm{gm}\sqrt{\frac{2\mathit{h}}{\mathit{g}}}$ $=\sqrt{2{\mathit{g}}_{\mathit{m}}\mathit{h}}\left({\mathit{g}}_{\mathit{m}}\simeq {\mathit{g}}_{\mathit{E}}∕6\right)$
speed at any moment is independent of mass, it depends only on gm and h.