If x+y=2 a, then the value of a{/ }(x-a)+a(y-a) is

None of the above/More than one of the above

BPSC 65th Re Prelims Exam 17 Feb 2020 Solved Paper

Question : 150 of 150

Marks: +1, -0

x+y=2 a

, then the value of

a{/ }(x-a)+a(y-a)

Solution:

\;{a}/{x-a}+\;{a}/{y-a}

=\;{a(y-a)+a(x-a)}/{(x-a)(y-a)}

=\;{a y-a^{2}+a x-a^{2}}/{(x-a)(y-a)}

=\;{a(x+y)-2 a^{2}}/{(x-a)(y-a)}=\;{a(2 a)-2 a^{2}}/{(x-a)(y-a)}

=\;{2 a^{2}-2 a^{2}}/{(x-a)(y-a)}=\;{0}/{(x-a)(y-a)}=0

Go to Question:

Prev Question