BPSC 65th Re Prelims Exam 17 Feb 2020 Solved Paper

Question : 144 of 150

Marks: +1, -0

If the product of three consecutive numbers is 120 , then the sum of those numbers is

Solution:

Let numbers are

x

x+1

and

x+2

From the question

x(x+1)(x+2)=120=4 × 5 × 6

∴ x+(x+1)+(x+2)=4+5+6=15

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