BPSC 64th Prelims Exam 16 Dec 2018 Solved Paper

Question : 140 of 150

Marks: +1, -0

The value of 40 degrees Celsius in Fahrenheit scale is

Solution:

The value of 40 degrees Celsius in Fahrenheit scale is

104^{∘} {F}

(40^{∘} {C} × 9 / 5)+32=104^{∘} {F}

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