BPSC 56th-59th Exam Prelims 15 Mar 2015 Solved Paper

Question : 124 of 150

Marks: +1, -0

Given, log 2 = 0.30103. Then log 5 is

Solution:

Since

\log 2=0.30103

\log 5=\log (\;{12}/{2})=\log 10-\log 2

\{\log \;{m}/{n}=\log m-\log n\}

=1-0.30103=0.6989

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