BPSC 56th-59th Exam Prelims 15 Mar 2015 Solved Paper

Question : 121 of 150

Marks: +1, -0

Let

f : R \to R

be defined by

f (x) = x^2 – 3x + 2

Then the value of f (f[5]) is

Solution:

f(x)=x^{2}-3 x+2

, f(5)=(5)^{2}-3 × 5+2=12

Again,

f(f(5))=(12)^{2}-3 × 5+2

=144-36+2=110

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