BPSC 53-55th Exam Prelims 17 Apr 2011 Solved Paper

Question : 73 of 150

Marks: +1, -0

The median of

2,4,6,8,10,12,

14,16 is

Solution:

Terms

2,4,6,8,10,

12,14,16
no. of terms

=8

(even)
so median

=\;{({8}/{2})^{\;\text "th "\;}+({8}/{2}+1)^{\;\text "th "\;} \;\text " term "\;}/{2}

=\;{(4^{\;\text "th "\;}+5^{\;\text "th "\;}) \;\text " term "\;}/{2}

=\;{8+10}/{2}=9

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