BPSC 48th to 52nd Exam Prelims 2008 Solved Paper

Question : 33 of 150

Marks: +1, -0

A coin is tossed upwards from the ground with a velocity of 9.8m/sec. Then it rises to a height of –

Solution:

∵ v^{2}=u^{2}-2 g h

0=(9.8)^{2}-2 × 9.8 × {h}

⇒ {h}=\;{9.8 × 9.8}/{2 × 9.8}=4.9 {m}

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