BPSC 45th Exam Prelims 2003 Solved Paper

Question : 113 of 150

Marks: +1, -0

Pointer for curve

x^2y^2 = a^2 (x^2 + y^2)

is parallel touch point at infinity

Solution:

x^{2} y^{2}=a^{2}(x^{2}+y^{2})

x^{2} y^{2}=a^{2} x^{2}+a^{2} y^{2}

x=± a

and

y=± a

Satisfies the above equation. So, these are the pointers for the curve

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