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Question : 98 of 130
Marks:
+1,
-0
Solution:
When the two lines intersect then shortest distance between them is zero i.e.
‌‌=0‌⇒(2−1)⋅1×2=0‌‌ where ‌1=+2+3,1=k+2+3‌2=2+3+,2=3+k+2‌⇒||=0‌⇒1(4−3k)−1(2k−9)−2(k2−6)=0‌⇒−2k2−5k+25=0⇒k=−5‌ or ‌‌
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