The torque of a force 5 \stackrel{\^}{i}+3 \stackrel{\^}{j}-7 \stackrel{\^}{k} about the origin is \tau. If the force acts on a particle whose position vector is 2 \stackrel{\^}{i}+2 \stackrel{\^}{j}+\stackrel{\^}{k}, then the value of \tau will be :

Correct Answer is : −17^i+19^j−4^k

11 \stackrel{\^}{i}+19 \stackrel{\^}{j}-4 \stackrel{\^}{k}

-11 \stackrel{\^}{i}+9 \stackrel{\^}{j}-16 \stackrel{\^}{k}

-17 \stackrel{\^}{ {\i}}+19 \stackrel{\^}{ {\j}}-4 \stackrel{\^}{ {\k}}

17 \stackrel{\^}{i}+9 \stackrel{\^}{j}+16 \stackrel{\^}{k}

BITSAT 2023 Shift 2 Solved Paper

Section: Physics

Question : 16 of 130

Marks: +1, -0

The torque of a force 5

−7

about the origin is τ. If the force acts on a particle whose position vector is 2

, then the value of τ will be :

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