BITSAT 2023 Shift 2 Solved Paper

Section: Mathematics

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Question : 119 of 130

Marks: +1, -0

If E and F are events such that 0<P(F)<1, then

P(E∣F)+P(E∣F)=1
P(E∣F)+P(E∣F)=1
P(E∣F)+P(E∣F)=1
P(E∣F)+P(E∣F)=0

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