\int \tan ^{-1} \sqrt{x} \dx is equal to

Correct Answer is : (x+1)tan−1√x−√x+C

(x+1) \tan ^{-1} \sqrt{x}-\sqrt{x}+C

x \tan ^{-1} \sqrt{x}-\sqrt{x}+C

\sqrt{x}-x \tan ^{-1} \sqrt{x}+C

\sqrt{ {\x}-( {\x}+1) \tan ^{-1} \sqrt{ {\x}+ {\C}

BITSAT 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 104 of 130

Marks: +1, -0

∫tan−1√x‌dx is equal to

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