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BITSAT 2021 Paper
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Section:
Chemistry
© examsiri.com
Question :
74 of 150
Marks:
+1
,
-0
X
‌
mL
of
H
2
gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is :
10 seconds : He
20 seconds:
O
2
25 seconds:
CO
55 seconds :
CO
2
Validate
Solution:
Under identical conditions,
r
1
r
2
=
√
M
2
M
1
As rate of diffusion is also inversely proportional to time, we will have,
t
2
t
1
=
√
M
2
M
1
(a) Thus, For He,
t
2
=
√
4
2
(
5
s
)
=
5
√
2
s
â‰
10
s
;
(b) For
O
2
,
t
2
=
√
32
2
(
5
s
)
=
20
s
(c) For
CO
,
t
2
=
√
28
2
(
5
s
)
â‰
25
s
;
(d) For
CO
2
,
t
2
=
√
44
2
(
5
s
)
â‰
55
s
© examsiri.com
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