BITSAT 2021 Paper

No. of lattice points = No. of octahedral voids =

1

2

× No. of tetrahedral voids in ccp structure
∴ No. of atoms of B = 4
No. of atoms of A=

1

2

× No. of octahedral voids
=

1

2

×4=2
No. of atoms of O= All tetrahedral voids =2× No. of lattice points =2×4=8
Hence, A:B:O=1:2:4
Therefore, the formula of the compound is AB2O4