The value of \\int\cos (\log x) \dx is :

Correct Answer is : x2[sin(logx)+cos(logx)]+C

\frac{1}{2}[\sin (\log x)+\cos (\log x)]+\C

\frac{x}{2}[\sin (\log x)+\cos (\log x)]+\C

\frac{x}{2}[\sin (\log x)-\cos (\log x)]+\C

\frac{1}{2}[\sin (\log x)-\cos (\log x)]+\C

BITSAT 2021 Paper

Section: Mathematics

Question : 116 of 150

Marks: +1, -0

The value of ∫cos(log‌x)‌dx is :

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