BITSAT 2020 Paper

The centre of the given circle is C≡(4,2)
Let A≡(−3,2) If (α,β) are the coordinates of the other end of the diameter, then, as the middle point of the diameter is the centre,
∴

α−3

2

=4 and

β+2

2

=2 ⇒α=11,β=2
Thus, the coordinates of the other end of diameter are (11,2).