BITSAT 2019 Slot 2 Solved Paper

Electronic configuration of Mn is (Z=25)=[Ar]3d54s2
∴ Electronic configuration of Mn4+ is Mn4+=[Ar]3d3
Thus, Mn4+ has 3 -unpaired electron and its spin only magnetic moment (µ) is, µ=√n(n+2)BM
where, n= number of unpaired electrons.
µ=√3(3+2).BM ⇒µ=√15=3.87BM≈4BM