A projectile is given an initial velocity of (\stackrel{\^}{{i}}+\\sqrt{3} \stackrel{\^}{{j}}) {m} \/ {s}, where \stackrel{\^}{{i}} is along the ground and \stackrel{\^}{{j}} is along the vertical. Then, the equation of the path of projectile is [\Take, g=10 {m} \/ {s}^{2}]

Correct Answer is : y=√3x−5x2

BITSAT 2019 Slot 2 Solved Paper

Section: Physics

Question : 31 of 150

Marks: +1, -0

A projectile is given an initial velocity of (

+√3

)m∕s, where

is along the ground and

is along the vertical. Then, the equation of the path of projectile is [Take,g=10m∕s2]

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