BITSAT 2019 Slot 2 Solved Paper

When capacitor is fully charged, then it acts like a open switch, therefore 8kΩ resistor has no use. So, rest of the resistances 4kΩ,7kΩ and 9kΩ will be in series.
Hence, current drawn from cell
I=

10

(4+7+9)×103

=

10

20×103

=0.5mA