If f'(x)=f(x)+\\int_{0} ^{1} f(x) d x, f(0)=1, then f(x)=

Correct Answer is : 2ex3−e+1−e3−e

{2 e^{x}}/{3-e}+\frac{1-e}{3-e}

{3 e^{x}}/{2-e}+\frac{1+e}{1-e}

{3 e^{x}}/{2-e}+\frac{1-e}{3+e}

BITSAT 2019 Slot 2 Solved Paper

Section: Mathematics

Question : 147 of 150

Marks: +1, -0

If f′(x)=f(x)+

∫

f(x)dx,f(0)=1, then f(x)=

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