(a) Since A moves twice the distance moved by B. If acceleration of B is ‘a’, then acceleration of A is ‘2a’. T' - (T +T) = 0 (since pulley is massless) ⇒ T' = 2T ....(i)
For 5 kg block 5g - T' = 5a for 2 kg block ⇒ 5g - 2T = 5a ....(ii) [ T’ = 2T ] T = 2 x (2a) = 4a ....(iii) From equations (ii) and (iii), 5g - (2 × 4a) = 5a 5g - 8a = 5a 5g = 13a a =