In Young's double slit experiment, intensity at a point is (\frac{1}{4}) of the maximum intensity. Angular position of this point is

Correct Answer is : sin−1(λ3d)

\sin ^{-1}(\frac{\\lambda}{2d})

\sin ^{-1}(\frac{\\lambda}{3d})

\sin ^{-1}(\frac{\\lambda}{4d})

BITSAT 2018 Slot 2 Solved Paper

Section: Physics

Question : 15 of 150

Marks: +1, -0

In Young's double slit experiment, intensity at a point is (

) of the maximum intensity. Angular position of this point is

Go to Question:

Prev Question

Next Question