BITSAT 2018 Paper

Time taken by same ball to return to the hands of juggler =

2u

g

=

2×20

10

= 4 s. So he is throwing the balls after each 1 s. Let at some instant he is throwing ball number 4. Before 1 sof it he throws ball. So height of ball 3 :
h3 = 20 × 1 -

1

2

10(1)2 = 15 m
Before 2s, he throws ball 2. So height of ball 2 :
h2 = 20 × 2 -

1

2

10(2)2 = 20 m
Before 3 s, he throws ball 1. So height of ball 1 :
h1 = 20 × 3 -

1

2

10(3)2 = 15 m