BITSAT 2018 Paper

The nuclear reaction is represented as follow:
‌817O→‌816O+‌01n
B.E per nucleon of ‌816O=7.97MeV
B.E per nucleon of 017=7.75MeV
Energy required to remove a neutron from ‌817O= ?
If mp represents the mass of a proton and mn that of a neutron, the energy required to remove a neutron from ‌817O is given by,
E= energy equivalent of ( mass of ‌816O+mn− mass of ‌817O)
=(8mp+8mn−7.97×16)+mn−(8mp+9mn−7.75×17)
=[7.75×17−7.97×16]MeV
=4.23MeV $