BITSAT 2017 Slot 2 Solved Paper

More be the number of unpaired electrons → more be the magnetic moment.
and
Number of unpaired electrons in Mg2+=0
Number of unpaired electrons in Ti3+=1
Number of unpaired electrons in V3+=2
Number of unpaired electrons in Fe2+=4
Thus, Fe2+ show maximum value of magnetic moment (µ). also, µ=√n(n+2).BM(n= Number of unpaired electrons).