BITSAT 2017 Slot 2 Solved Paper

Equation of wave,
y=0.2‌sin[1.5x+60t]
Comparing with standard equation, we get
y=A‌sin[kx+ωt]
k=1.5=

2π

λ

and ω=60=

2π

T

∴ Velocity of wave, v=

ω

k

=

60

1.5

=40m∕s
Velocity of wave in stretched string, v=√

T

m

,
where, m is the linear density, T is tension in the string.
So, T=v2m=(40)2×3×10−4
=0.48N