The de-Broglie wavelength of a proton (charge =1.6 \\times10^{-19} {C}, m=1.6 \\times10^{-27} {kg}) accelerated through a potential difference of 1 {kV} is

Correct Answer is : 0.9×10−12m

BITSAT 2017 Slot 2 Solved Paper

Section: Physics

Question : 14 of 150

Marks: +1, -0

The de-Broglie wavelength of a proton (charge =1.6×10−19C,m=1.6×10−27kg) accelerated through a potential difference of 1kV is

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