BITSAT 2017 Slot 2 Solved Paper

Given, equation of hyperbola is
(10x−5)2+(10y−4)2=λ2(3x+4y−1)2 can be rewritten as

√(x− 1 2 )2+(y− 2 5 )2

| 3x+4y−1 5 |

=|

λ

2

|
This is of the form of

PS

PM

=e
Where, P is any point on the hyperbola and S is a focus and M is the point of directrix.
Here, |

λ

2

|>1⇒|λ|>2(∵e>1)
⇒λ<−2 or λ>2