BITSAT 2016 Paper

Section: Mathematics

© examsiri.com

Question : 86 of 150

Marks: +1, -0

The general solution of the equation sin‌2‌x+2‌sinx+2‌cosx+1=0 is

3nπ−
π
4
2nπ−
π
4
2=nπ+(−1)nsin−1(‌‌
1
√3
)
nπ−
π
4

Go to Question:

Prev Question

Next Question