BITSAT 2016 Paper

As shown in the figure, the wires will have the sameYoung’s modulus (same material) and the length of the wire of area of cross-section 3A will be A/3 (same volume as wire 1).
For wire 1,Y=‌‌

F A

∆ x l

....(1)
For wire 2,Y=‌‌

FI 3 A

∆ x ( l 3 )

...(2)
From (i) and (ii)