Formation of polyethylene from calcium carbide takes place as follows {CaC}_{2}+2{H}_{2}{O}\rightarrow{Ca}({OH})_{2}+{C}_{2}{H}_{2} {C}_{2}{H}_{2}+{H}_{2}\rightarrow{C}_{2}{H}_{4} {nC}_{2}{H}_{4}\rightarrow(-{CH}_{2}-{CH}_{2}-)_{{n}} The amount of polyethylene obtained from 64.1 kg of CaC_2 is

BITSAT 2016 Paper

Section: Chemistry

Question : 56 of 150

Marks: +1, -0

Formation of polyethylene from calcium carbide takes place as follows

CaC2+2H2O⟶Ca(OH)2+C2H2

C2H2+H2⟶C2H4
nC2H4⟶(−CH2−CH2−)n
The amount of polyethylene obtained from 64.1 kg of CaC2 is

Go to Question:

Prev Question

Next Question