BITSAT 2015 Paper

U = {x : x5–6x4+11x3–6x2 = 0}
Solving for values of x, we get
U = {0, 1, 2, 3}
A = {x : x2 – 5x + 6 = 0}
Solving for values of x, we get
A = {2, 3}
and B = {x : x2 – 3x + 2 = 0}
Solving for values of x, we get
B = {2, 1}
A ∩ B = {2}
∴ (A ∩ B)' = U – (A ∩ B)
= {0, 1, 2, 3} – {2} = {0, 1, 3}