BITSAT 2015 Paper
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Question : 22 of 150
Marks:
+1,
-0
The position of a projectile launched from the origin at t = 0 is given by
= (40
+ 50
)m at t = 2s. If the projectile was launched at an angle q from the horizontal, then θ is (take g = 10 m s – 2 )
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