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Question : 100 of 150
Marks:
+1,
-0
Solution:
Let y =
(cosecx)1∕logx Taking log on both sides, we get
log y =
[‌form] =
(By L' Hospital rule)
= -
(Since cot x =
)
⇒ log y = - 1
⇒ y =
e−1 =
Hence, required limit =
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