BITSAT 2013 Paper

Equation of the line making intercepts a and b on the axes is

x

a

+

y

b

= 1
Since, it passes through (1, 1)
⇒

1

a

+

1

b

= 1 ... (i)
Also the area of the triangle formed by the line and the axes is A.
∴

1

2

ab = A ⇒ ab = 2a ... (ii)
From eqs. (i) and (ii), we get, a + b = 2A
Hence, a and b are the roots of the eq.
x2 - (a + b)x + ab = 0 ⇒ x2 - 2Ax + 2A = 0